Task 1: Loop mix-up: Snippet 1
This task is a mixed text/programming task. You need to update the content of loop.cpp according to the instruction provided in the file. For the code part, please check the autograder output.
Task
Considering the snippet
int n;
std::cin >> n;
int f = 1;
if (n > 0) {
do {
f = f * n;
--n;
} while (n > 0);
}
std::cout << f << std::endl;- Describe what it computes.
- Decide which of the other two kind of loops would fit better than the one it is currently using, and describe why.
- Rewrite the snippet into the loop you specified in (2). This part is autograded.
Important: The use of goto statements is prohibited.
Solution
#include "loop.h"
#include <iostream>
// Fill out the file with the required answers
/*
Subtask 1: describe what the code snippet computes
It calculates the factorial of the number inputed by the user.
*/
/*
Subtask 2: decide which of the other two kind of loops would fit better, and
describe why.
Just a simple for loop would suffice the task of this code snippet, as we can
define the condition in the for loop as well as the expression. This
simplifies the code alot.
Of course we could also include the edge case where the input n is 0 or
smaller than zero. In this case an if statement would be more of use since we
have to seperate the cases.
*/
/*
Subtask 3: update the function below by rewriting the snippet into the
loop you specified in (2)
*/
void loop() {
int n;
std::cin >> n;
int f = 1;
for (; n > 0; --n)
f = f * n;
std::cout << f << std::endl;
}-——
Made by JirR02 in Switzerland 🇨🇭