Converted everything to orgmode
converted everything to orgmode and added solution to the README files
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@@ -6,14 +6,14 @@ This task is a text based task. You do not need to write any program/C++ file: t
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* Task
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Which of the following expressions evaluate to `true`, which to `false`?
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Which of the following expressions evaluate to =true=, which to =false=?
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1. `3 >= 3`
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1. `true || false && false`
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1. `(true || false) && false`
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1. `3 > (1 < true)`
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1. `8 > 4 > 2 > 1`
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1. `2 < a < 4` (a is a variable of type int)
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1. =3 >= 3=
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1. =true || false && false=
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1. =(true || false) && false=
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1. =3 > (1 < true)=
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1. =8 > 4 > 2 > 1=
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1. =2 < a < 4= (a is a variable of type int)
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* Solutions
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@@ -3,9 +3,9 @@
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* Task
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Translate the following natural language expressions to `C++` expressions. Assume that all the variables are non-negative integers or boolean (of value `true` or `false`).
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Translate the following natural language expressions to =C++= expressions. Assume that all the variables are non-negative integers or boolean (of value =true= or =false=).
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/For this task you need to write the solutions in the `solutions.cpp` file, by filling the various functions that have been defined for each subtasks./
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/For this task you need to write the solutions in the =solutions.cpp= file, by filling the various functions that have been defined for each subtasks./
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*Example:* \(a\) is greater than \(3\) and smaller than \(5\). \(\Longrightarrow\) *Solution:*
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@@ -13,7 +13,7 @@ Translate the following natural language expressions to `C++` expressions. Assum
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return a > 3 && a < 5;
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#+end_src
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/Note:/ Do not confuse the bitwise logical operators (e.g., `&`) with their binary logical counterparts (`&&`). The semantics are slightly different — bitwise operators do not exhibit short circuit evaluation.
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/Note:/ Do not confuse the bitwise logical operators (e.g., =&=) with their binary logical counterparts (=&&=). The semantics are slightly different — bitwise operators do not exhibit short circuit evaluation.
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1. \(a\) greater than \(b\) and the difference between \(a\) and \(b\) is smaller than \(15\).
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1. \(a\) is an even natural number greater than \(a\).
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@@ -23,9 +23,9 @@ return a > 3 && a < 5;
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** Input
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The program expects the task number as the first input followed by the parameters to the chosen task. For example, `3 5 1 1` selects task `3` with `a = 5`, `b = 1`, and `c = 1`.
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The program expects the task number as the first input followed by the parameters to the chosen task. For example, =3 5 1 1= selects task =3= with =a = 5=, =b = 1=, and =c = 1=.
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Note that boolean parameters for tasks 4 and 5 are entered as true and false. For example `4 true false true` would run task `4` with `a = true`, `b = false`, and `c = true`.
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Note that boolean parameters for tasks 4 and 5 are entered as true and false. For example =4 true false true= would run task =4= with =a = true=, =b = false=, and =c = true=.
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* Solutions
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@@ -80,3 +80,7 @@ bool task5(bool a, int b) {
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}
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}
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#+end_src
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-----
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Made by JirR02 in Switzerland 🇨🇭
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@@ -20,7 +20,7 @@ If your program is asked to print the Fibonacci primes between $0$ and $14$ the
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Found 4 Fibonacci primes
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#+end_src
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*Important:* using anything other than `int` (e.g., `unsigned int`, floating point numbers, `long`, or double `long`) is forbidden.
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*Important:* using anything other than =int= (e.g., =unsigned int=, floating point numbers, =long=, or double =long=) is forbidden.
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* Solutions
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@@ -7,17 +7,17 @@
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* Task
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Fibonacci numbers grow fast, and can thus easily exceed the value range of 32-bit `int`. Think of a general way how you can check if the result of an addition would exceed the range of a 32-bit `int` (i.e. overflow) *without actually performing the addition causing the overflow.*
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Fibonacci numbers grow fast, and can thus easily exceed the value range of 32-bit =int=. Think of a general way how you can check if the result of an addition would exceed the range of a 32-bit =int= (i.e. overflow) *without actually performing the addition causing the overflow.*
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Remember that we consider *signed integers.* Because only half of the numbers are positive, this leaves us with 31 bits to store the actual positive number value.
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Write a program that asks the user for an integer \(n\) and then prints the first $n$ Fibonacci numbers, each number on a new line. Use an `int` (we assume 32 bits, including the sign) to represent the current Fibonacci number. *Most importantly:* exit the print loop as soon as you detect that an overflow /would occur./
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Write a program that asks the user for an integer \(n\) and then prints the first $n$ Fibonacci numbers, each number on a new line. Use an =int= (we assume 32 bits, including the sign) to represent the current Fibonacci number. *Most importantly:* exit the print loop as soon as you detect that an overflow /would occur./
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Finally, again on a new line, output the count \(c\) of Fibonacci numbers previously printed, and the initial input \(n\) from the user, in the format: `c of n`.
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Finally, again on a new line, output the count \(c\) of Fibonacci numbers previously printed, and the initial input \(n\) from the user, in the format: =c of n=.
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** Example:
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Let's (wrongly!) assume that \(5\) cannot be represented using a 32 bit `int`. This means that \(3\) is the largest 32-bit Fibonacci number. If your program is asked to print the first \(4\) Fibonacci numbers the output should look as follows:
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Let's (wrongly!) assume that \(5\) cannot be represented using a 32 bit =int=. This means that \(3\) is the largest 32-bit Fibonacci number. If your program is asked to print the first \(4\) Fibonacci numbers the output should look as follows:
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#+begin_src shell
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0
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@@ -38,7 +38,7 @@ If you instead ask it to print the first 100 Fibonacci numbers the output should
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Printed 5 of 100 Fibonacci numbers
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#+end_src
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*Important:* using anything other than `int` (e.g., `unsigned int`, floating point numbers, `long`, or double `long`) is forbidden.
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*Important:* using anything other than =int= (e.g., =unsigned int=, floating point numbers, =long=, or double =long=) is forbidden.
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*Restrictions:*
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@@ -56,7 +56,7 @@ Printed 5 of 100 Fibonacci numbers
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* Mistakes
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- The variable `j` goes into overflow which is not allowed!
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- The variable =j= goes into overflow which is not allowed!
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* Solution
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@@ -3,7 +3,7 @@
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* Task
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Write a program that inputs a non-negative integer `n` (but store it as `int`) and outputs the binary digits of `n` in the /correct/ order (i.e., starting with the most significant bit). Do not output the leading zeros or the sign.
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Write a program that inputs a non-negative integer =n= (but store it as =int=) and outputs the binary digits of =n= in the /correct/ order (i.e., starting with the most significant bit). Do not output the leading zeros or the sign.
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*Hint:* In order to find the largest integer \(k\) such that \(2^k \leq x\), you can utilize that \(k\) is the smallest integer such that \(2^k > \frac{x}{2}\). This observation is particularly useful to avoid an overflow for the expression \(2^k\) when searching for the most significant bit to represent \(x\).
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